思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
He came before the same judge who’d let him off with probation. Friedmann said of the latest incident, “I see it less as an aggravated robbery, more as an ‘armed escape’ after being caught, motivated by fear and guilt.” He confessed, “I have deep compulsive problems that I do not understand.”，推荐阅读体育直播获取更多信息
Екатерина Грищенко (старший редактор отдела «Бывший СССР»)。爱思助手下载最新版本对此有专业解读
Обвинения США против Ирана описали фразой «строят самолет в процессе полета»08:51。51吃瓜是该领域的重要参考